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Please refers to the following website :http://img154.imageshack.us/img154/6610/blockxx4.pngBlock A of mass 5kg is placed on a rough inclined plane and is connected to block B of mass 8kg by a light inextensible string, passing over a pulley as shown in the figure. Block A moves up the inclined plane with an... 顯示更多 Please refers to the following website : http://img154.imageshack.us/img154/6610/blockxx4.png Block A of mass 5kg is placed on a rough inclined plane and is connected to block B of mass 8kg by a light inextensible string, passing over a pulley as shown in the figure. Block A moves up the inclined plane with an acceleration of 2ms^-2 . (i) What is the tension in the string ? (ii) What is the friction between block A and the inclined plane ?
最佳解答:
i. The whole system is accelerating with an acceleration of 2 ms-2. Consider block B By Newton's 2nd law of motion mBg - T = mBa (8)(10) - T = (8)(2) Tension in the string, T = 64 N b. Let f be the frictional force between block A and the inclined plane. As block A is moving up the plane, the frictional force is acting in the direction down the plane. Hence, by Newton's 2nd law of motion, T - mAgsin30* - f = mAa 64 - (5)(10)sin30* - f = (5)(2) f = 29 N
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A question on mechanics發問:
Please refers to the following website :http://img154.imageshack.us/img154/6610/blockxx4.pngBlock A of mass 5kg is placed on a rough inclined plane and is connected to block B of mass 8kg by a light inextensible string, passing over a pulley as shown in the figure. Block A moves up the inclined plane with an... 顯示更多 Please refers to the following website : http://img154.imageshack.us/img154/6610/blockxx4.png Block A of mass 5kg is placed on a rough inclined plane and is connected to block B of mass 8kg by a light inextensible string, passing over a pulley as shown in the figure. Block A moves up the inclined plane with an acceleration of 2ms^-2 . (i) What is the tension in the string ? (ii) What is the friction between block A and the inclined plane ?
最佳解答:
i. The whole system is accelerating with an acceleration of 2 ms-2. Consider block B By Newton's 2nd law of motion mBg - T = mBa (8)(10) - T = (8)(2) Tension in the string, T = 64 N b. Let f be the frictional force between block A and the inclined plane. As block A is moving up the plane, the frictional force is acting in the direction down the plane. Hence, by Newton's 2nd law of motion, T - mAgsin30* - f = mAa 64 - (5)(10)sin30* - f = (5)(2) f = 29 N
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