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標題:

6x^4-7x^3+ax^2+3x+2能被x^2-x+b整除

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發問:

6x^4-7x^3+ax^2+3x+2能被x^2-x+b整除求a,b

最佳解答:

As follows: 圖片參考：http://f.imagehost.org/0577/ScreenHunter_05_Jan_29_22_49.jpg 2010-01-30 13:30:17 補充： 6x^4 – 7x^3 + ax^2 + 3x + 2 = (x^2 – x + b)(6x^2 + cx + m) = 6x^4 – 6x^3 + 6bx^2 + cx^3 – cx^2 + bcx + mx^2 – mx + bm = 6x^4 + (c – 6)x^3 + (6b – c + m)x^2 + (bc – m)x + bm c – 6 = -7 => c = -1 a = 6b + 1 + m … (1) 3 = -b – m … (2) bm = 2 … (3) 2010-01-30 13:30:40 補充： (2) => b = -3 – m Sub into (3), (-3 – m)m = 2 m^2 + 3m + 2 = 0 (m + 1)(m + 2) = 0 m = -1 or m = -2 m = -1 => b = -2 => a = -12 + 1 – 1 = -12 m = -2 => b = -1 => a = -6 + 1 – 2 = -7

其他解答:

thx你先 不過可5可以用意用(x^2-x+b)(6x+cx+m)做一次泥thx