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標題:
ALGEBRA, BINARY OPERATION
發問:
Let S be an arbitrary non-empty set, x,y,z is in S, and suppose that * is an associative binary operation on S. Prove: if x*y=y*x and x*z=z*x, then x*(y*x)=(y*z)*x. Please provide full proof step and clear explanation Thankssssssss
x*(y*x)=(y*z)*x is not true when z =/= x and S = the set of positive integers and * = usual multiplication. I think your question is to prove x*(y*z) = (y*z)*x. x*(y*z) = (x*y)*z (since the binary operation * is associative) = (y*x)*z (since x*y = y*x from assumption) = y*(x*z) (since the binary operation * is associative) = y*(z*x) (since x*z=z*x from assumption) = (y*z)*x (since the binary operation * is associative)
其他解答:
這裏可以幫到你 http://aciowinw.b5.55zz.net/yahoo.com.hk/hk/auction/178987536
ALGEBRA, BINARY OPERATION
發問:
Let S be an arbitrary non-empty set, x,y,z is in S, and suppose that * is an associative binary operation on S. Prove: if x*y=y*x and x*z=z*x, then x*(y*x)=(y*z)*x. Please provide full proof step and clear explanation Thankssssssss
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最佳解答:x*(y*x)=(y*z)*x is not true when z =/= x and S = the set of positive integers and * = usual multiplication. I think your question is to prove x*(y*z) = (y*z)*x. x*(y*z) = (x*y)*z (since the binary operation * is associative) = (y*x)*z (since x*y = y*x from assumption) = y*(x*z) (since the binary operation * is associative) = y*(z*x) (since x*z=z*x from assumption) = (y*z)*x (since the binary operation * is associative)
其他解答:
這裏可以幫到你 http://aciowinw.b5.55zz.net/yahoo.com.hk/hk/auction/178987536
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